How much force is tending to pull Rover forward?

A woman takes her dog Rover for a walk on a leash. To get the little pooch moving forward, she pulls on the leash with a force of 21.0 N at an angle of 37.0 degrees above the horizontal.





How much force is tending to pull Rover forward?





How much force is tending to lift Rover off the ground?








I need help solving this problem please! : )|||Forward force component = 21 . cos 37˚





Vertical ( upward) force component = 21 sin 37˚





Thats about all that can be said.|||what are the degrees N or forward force?

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|||fx = P cos(theta); where P = 21 N and theta = 37 deg, fx is the pull forward.





fy = P sin(theta) is the pull up off the ground. You can do the math.





This is just trigonometry, very little physics. P is a vector; it has both magnitude (21 N) and direction (37 deg). That means it can be broken into its two component vectors fx and fy.





Note that P^2 = fx^2 + fy^2 = (P cos(theta))^2 + (P sin(theta))^2 = P^2 (cos(theta)^2 + sin(theta)^2) = P^2; so that 1 = sin(theta)^2 + cos(theta)^2 which is a trig identify you should memorize.